3x^2-300x-14000=0

Solution for 3x^2-300x-14000=0 equation:

3x^2-300x-14000=0

a = 3; b = -300; c = -14000;
Δ = b2-4ac
Δ = -3002-4·3·(-14000)
Δ = 258000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{258000}=\sqrt{400*645}=\sqrt{400}*\sqrt{645}=20\sqrt{645}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-20\sqrt{645}}{2*3}=\frac{300-20\sqrt{645}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+20\sqrt{645}}{2*3}=\frac{300+20\sqrt{645}}{6}
$